Overloading conversion operator from int to std::string

Question

Is it possible to overload conversion operator from int to std::string? Is it possible to use this function:

void printToLog(std::string text);

Like this:

int a = 5;
printToLog(a);

Or this:

int a = 5;
printToLog(a + " bombs have been planted.");

?

StoryTeller - Unslander Monica · Accepted Answer · 2017-11-12T16:58:42.813

0

There's a function for it in the standard library. The aptly named std::to_string:

int a = 5;
printToLog(std::to_string(a) + " bombs have been planted.");

You cannot add a conversion operator for this purpose. Such an operator can only be a member of a class type, and int is not a class type. Neither can you add a converting constructor to std::string. Use the mechanism the standard gives you.

edited Nov 12 '17 at 16:58

answered Nov 12 '17 at 16:55

StoryTeller - Unslander Monica

165,132
21
377
458

I know, but I'm asking: Is it possible to make conversion operator from int to std::string? – lollypap54 Nov 12 '17 at 16:56
@lollypap54 - No. And why would one do that? To avoid some typing? It's a bad reason. – StoryTeller - Unslander Monica Nov 12 '17 at 16:59
Well yeah, it's pretty bad for this exact purpose, but sometimes you just want to know: is it possible? :/ – lollypap54 Nov 12 '17 at 17:04
1

@lollypap54 - Like I already said. No. – StoryTeller - Unslander Monica Nov 12 '17 at 17:04

Overloading conversion operator from int to std::string

1 Answers1