how to get key as words in dictionary?

Question

If I have this dictionary how can I do to get the key instead value but reading words. Example if I write 2 22 1 response must be A B .

value= {"A": 2, "B": 22, "C": 222, "D": 3, "E": 33,"F":333, "G": 4, "H": 44, "I": 444, "J": 5, "K": 55, "L": 555, "M": 6, "N": 66, "O": 666, "P": 7, "Q": 77, "R": 777, "S": 7777, "T": 8, "U": 88, "V": 888, "W": 9, "X": 99, "Y": 999, "Z": 9999}

I was trying with this loop but there´s something wrong:

for i in r:
  key= n[i]
  print key

I know but I can´t figure out how to use a list or a tuple with this — apk, Nov 14 '17 at 02:38

Ajax1234 · Accepted Answer · 2017-11-14T02:04:06.123

0

You can reverse the dictionary:

value= {"A": 2, "B": 22, "C": 222, "D": 3, "E": 33,"F":333, "G": 4, "H": 44, "I": 444, "J": 5, "K": 55, "L": 555, "M": 6, "N": 66, "O": 666, "P": 7, "Q": 77, "R": 777, "S": 7777, "T": 8, "U": 88, "V": 888, "W": 9, "X": 99, "Y": 999, "Z": 9999} 
new_value = {b:a for a, b in value.items()}
print(new_value[2])

Output:

Regarding your latest comment, you can try this:

final_results = [a for a, b in value.items() if b == 22]

edited Nov 14 '17 at 02:04

answered Nov 14 '17 at 01:43

Ajax1234

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Caveat: the values must be unique, or you will overwrite early entries. – Reblochon Masque Nov 14 '17 at 01:44
but if it´s a large string it doesn´t work, only read the first character – apk Nov 14 '17 at 01:56
@apk what do you mean by large string? A string that does not exist in the values or keys? – Ajax1234 Nov 14 '17 at 01:58
if I type '22' the response is only 'A' not 'B' – apk Nov 14 '17 at 02:01
@apk I made an edit to fix the list based solution. However, when I tried `new_value[22]` the program did indeed output 'B' – Ajax1234 Nov 14 '17 at 02:05
thanks, don´t have the answer to my question but you gave me an idea – apk Nov 14 '17 at 02:17

how to get key as words in dictionary?

1 Answers1