1

PHP CODE:

echo json_encode($data);

JQUERY AJAX:

$(".comment").click(function(){
    var id  =  $(this).data("id");
    var name = $("#username_"+id).val();

    if(name=='') {
        alert("Please Fill All Fields");
    } else {
        $.ajax({
            type: "POST",
            url: "comments",
            data:{comments:name,parent:id},
            dataType: 'json',
            success: function(json) {
                json.forEach(function (item, index){
                    var br = "<br>";
                    var url = "http://localhost/projects/quotes/assets/uploads/avatar/";
                    $(".cmt_comments img").append(""+url+item.image+"");
                    $(".cmt_comments").append(item.comments,br);
                });
            }
        });
    }
});

JSON ARRAY:

[{"image":"1510553363_User_Avatar_2.png","comments":"NICE"}] 

HTML:

<div class="cmt_comments">
    <img src="" alt="">
</div>

OUTPUT:

http://localhost/projects/quotes/assets/uploads/avatar/1510553363_User_Avatar_2.pnghttp://localhost/projects/quotes/assets/uploads/avatar/1510553363_User_Avatar_2.png

NICE

I want:

Now display only image url. how to i display image
julianstark999
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0 Answers0