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I am working in an app that connects to a Siemens PLC using LibnoDave library. I am getting a Dword value that I convert it into an INT value, but now I need to convert this INT value into a BIT array. For example, I get as a INT value the number 62000 that in binary is ‭1111001000110000‬. I need that value. How can this be done?

Botez Adrian
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    Possible duplicate of [Convert int to a bit array in .NET](https://stackoverflow.com/questions/6758196/convert-int-to-a-bit-array-in-net) – Salem Nov 16 '17 at 07:08

2 Answers2

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If you want to represent uint in binary, try using Convert class:

  uint source = 62000;

  string result = Convert.ToString(source, 2);

  Console.WriteLine(result);

Outcome

  1111001000110000

If you want System.Collections.BitArray instance:

  using System.Collections;
  using System.Linq; 

  ...

  uint source = 62000;

  BitArray array = new BitArray(BitConverter.IsLittleEndian 
    ? BitConverter.GetBytes(source)
    : BitConverter.GetBytes(source).Reverse().ToArray());

  // Test
  string result = string
    .Concat(array
       .OfType<bool>()
       .Reverse()
       .Select(item => item ? 1 : 0))
    .TrimStart('0');

  Console.WriteLine(result);

Outcome

  1111001000110000
Dmitry Bychenko
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    Is `Convert.ToString` always treat number as big endian? Side note: `TrimStart('0')` seems to be unnecesasry. If you for example use `uint source = 0` - result will be empty string, while expected result (I think) is string with 16 zeroes. – Evk Nov 16 '17 at 07:38
  • @Evk: Thank you! I agree with endians check; but since the `result` just demonstrates `array` contains correct data (for a single `62000` test) let me keep `TrimStart` as it is. – Dmitry Bychenko Nov 16 '17 at 07:46
  • But that's because you use `uint`. Since OP says that 62000 is represented as 2 bytes - you have to use `ushort`. `INT` he uses in question can mean anything, because as I understand it's not C# int. And with `ushort` you can remove `TrimStart`. Your endianess check is also a bit strange, because you reverse once if `BitConverter` is not little endian, and then you reverse once again when working with BitArray. So you need to reverse if BitConverter is little endian and remove `Reverse()` when doing `Concat`. – Evk Nov 16 '17 at 07:49
  • If I understand the question right, it's about `DWORD` https://msdn.microsoft.com/en-us/library/cc230318.aspx "**32-bit** unsigned integer", that's why I've put `uint` (`UInt32`) – Dmitry Bychenko Nov 16 '17 at 07:54
  • Well he converts DWORD into some INT value, and that INT value he needs to convert to bit array (maybe INT is https://msdn.microsoft.com/en-us/library/cc230334.aspx in which case we are both wrong). Anyway, OP indeed can decide himself what he means. – Evk Nov 16 '17 at 07:57
  • `BitArray` starts from lower bit, e.g. `BitArray array = [true, false]` represents `2` but we want reversed `10` test outcome; just put `byte source = 2;` (in order to eliminate endians effect) and, please, see; – Dmitry Bychenko Nov 16 '17 at 07:58
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The question is that in that DWORD I only need the second word. For exampel if I receive 11111111111111110000000000000000 , I only need the 1111111111111111 of this Dword.

Botez Adrian
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