non-standard syntax; use '&' to create a pointer to member. Accessing boolean variable

Question

I've been searching for a while on why this does not work. I have not gotten a clear answer.

Can anyone explain why trying to access this boolean variable and comparing it to another boolean variable won't work?

I also tried setting the rhs of the comparison to 0, and that got rid of the boolean/int error, but I'm still getting the error.

#include <iostream>

using namespace std;

class MyClass {
public:
    MyClass() {
        setWorking(true);
    }

    //Mutator
    void setWorking(bool x) { working = x; }

    //Accessor
    bool getWorking() { return working; }

private:
    bool working;
};

int main() {

    MyClass alpha;

    if (alpha.getWorking == true) {
        cout << "its working\n";
    }
    else {
        cout << "not working\n";
    }

    return 0;
}

[`using namespace std;` is a bad practice](https://stackoverflow.com/q/1452721/2176813), never use it. — tambre, Nov 16 '17 at 18:14
I cant believe I forgot (). Ive been trying to fix this for almost 2 hours. Thank you so much — GreenEggsAndRam, Nov 16 '17 at 18:15
You also didn't bother searching for your error message. You would have found dozens of similar questions. — Barmar, Nov 16 '17 at 18:16

score 1 · Answer 1 · answered Nov 16 '17 at 18:18

1

In main function

if (alpha.getWorking == true)

should be

if (alpha.getWorking())

answered Nov 16 '17 at 18:18

Yousaf

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I think the comments already covered it... – Steve Nov 16 '17 at 18:23

non-standard syntax; use '&' to create a pointer to member. Accessing boolean variable

1 Answers1