How to get successive base classes in typescript

Question

I'd like to walk up the super type chain all the way to Object, so given:

abstract class Foo {}

abstract class Bar extends Foo {}

abstract class Baz extends Bar {}

class Yolo extends Baz {}

let yolo = new Baz()

How can I get all the extended classes Baz, Bar, Foo, and Object with an instance of yolo?

I saw How to get the parent class at runtime and I don't see how that would help me, I can only go up one level.

score 2 · Accepted Answer · answered Nov 18 '17 at 15:08

You can use getPrototypeOf successively to walk up the super chain:

var ctor = yolo.constructor;
while(ctor !== null){
    console.log(ctor);
    ctor = Object.getPrototypeOf(ctor);    
}

Will output:

function Yolo() { … }
function Baz() { … }
function Bar() { … }
function Foo() { … }
function () { … }
Object { … }

1 Answers1