I have the following dataframe:
1 2 3 4 5 6 7 8 9 10
cat cat 1 1 1 1 1 1 0 0 1 1
dog 1 0 1 1 1 1 0 0 1 1
fox 0 0 0 0 0 0 0 0 0 0
jumps 1 0 1 1 1 0 0 1 1 1
over 1 0 1 1 1 1 0 0 1 1
the 1 0 1 1 1 1 0 0 1 1
dog cat 1 1 0 1 1 1 0 0 1 0
dog 1 1 1 1 1 1 0 0 1 1
fox 1 1 1 1 1 1 0 0 1 1
jumps 1 1 1 1 1 1 0 1 1 1
over 1 1 1 1 1 1 0 0 1 1
the 1 1 1 1 1 1 1 0 1 1
fox cat 0 0 0 0 0 0 0 0 0 0
dog 1 1 1 1 1 1 0 0 1 1
fox 1 1 1 1 1 1 0 0 1 1
jumps 1 1 1 1 1 1 0 1 1 1
over 1 1 1 1 1 1 0 0 1 1
the 1 1 1 1 1 1 1 0 1 1
jumps cat 1 1 0 1 0 1 1 0 1 0
dog 1 1 1 1 1 1 1 0 1 0
fox 1 1 1 1 1 1 1 0 1 0
jumps 1 1 1 1 1 1 0 0 1 0
over 1 0 1 1 1 0 0 1 1 0
the 1 0 1 1 1 1 0 0 1 0
over cat 1 1 0 1 1 1 0 0 1 0
dog 1 1 1 1 1 1 0 0 1 0
fox 1 1 1 1 1 1 0 0 1 0
jumps 1 1 0 1 0 1 1 0 1 0
over 1 1 1 1 1 1 0 0 1 0
the 1 0 1 1 1 0 0 1 1 0
the cat 1 1 0 1 1 1 0 0 1 0
dog 1 1 1 1 1 1 0 1 1 0
fox 1 1 1 1 1 1 0 1 1 0
jumps 1 1 0 1 1 1 0 0 1 0
over 1 1 0 1 0 1 1 0 1 0
the 1 1 1 1 1 1 0 0 1 0
As you can see the first two columns are unlabelled. I want to select all rows where column1 == 'dog'
So that I end up with this:
dog cat 1 1 0 1 1 1 0 0 1 0
dog dog 1 1 1 1 1 1 0 0 1 1
dog fox 1 1 1 1 1 1 0 0 1 1
dog jumps 1 1 1 1 1 1 0 1 1 1
dog over 1 1 1 1 1 1 0 0 1 1
dog the 1 1 1 1 1 1 1 0 1 1
If it had a label, the solution would have been:
print(df.loc[df['label'] == 'dog'])
But because it doesn't have a label, how do I achieve that? Any suggestions will be highly appreciated. Thank you.