PHP combinations two by two

Question

I searched the site but I could not find what I need and I do not know how to do this code. I need a script to make all the combinations in an array

For example i have this array:

$players = ('1', '2', '3', '4', '5');

And i need this output

Thanks in advance

Possible duplicate of [Permutations - all possible sets of numbers](https://stackoverflow.com/questions/5506888/permutations-all-possible-sets-of-numbers) — Delpes, Nov 23 '17 at 10:33
I don't think that is a good duplicate. That question is much more advanced than this one — Andreas, Nov 23 '17 at 10:34
2x nested foreach loops, 1x call to array_slice(), 1x echo statement.... not exactly complicated — Mark Baker, Nov 23 '17 at 10:37

kscherrer · Accepted Answer · 2017-11-23T14:32:36.657

2

$players = array('1','2','3','4','5');

while(count($players) != 0){
    $currentPlayer = array_shift($players);
    foreach($players as $player){
        echo $currentPlayer.' - '.$player.'<br/>';
    }
}

Edit: My code works, even if the playernumbers are nonconsecutive. The $players array can look like this $players = ('1','5','209','42'); and still print out the desired output.

edited Nov 23 '17 at 14:32

answered Nov 23 '17 at 10:45

kscherrer

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Yes. I saw. Thank you for your answer :) – Cristian Longo Nov 23 '17 at 10:56
declare array properway:-- $players =array ('1','2','3','4','5'); – Harveer Singh Aulakh Nov 23 '17 at 11:30

score 0 · Answer 2 · answered Nov 23 '17 at 10:52

simple way :--

function combinations($arr, $n)
{
    $res = array();

    foreach ($arr[$n] as $item)
    {
        if ($n==count($arr)-1)
            $res[]=$item;
        else
        {
            $combs = combinations($arr,$n+1);

            foreach ($combs as $comb)
            {
                $res[] = "$item $comb";
            }
        }
    }
    return $res;
}

$words = array(array('A','B'),array('C','D'), array('E','F'));

$combos = combinations($words,1);  
echo '<pre>';
print_r($combos);
echo '</pre>';
?>

output:--

Array
(
    [0] => C E
    [1] => C F
    [2] => D E
    [3] => D F
)

score 0 · Answer 3 · answered Nov 23 '17 at 11:03

  $players = array('1', '2', '3', '4', '5');

          for($i=0;$i<sizeof($players)-1;$i++){
               for($j=$i;$j<sizeof($players);$j++){
                   if( $players[$i]!= $players[$j]){
                          echo  '<br/>';
                       echo $players[$i].' - '.$players[$j];
                   }
              }
          }

Output -

Fky · Answer 4 · 2017-11-23T10:42:10.703

-1

try this :

<?php
  $arr = array('1','2', '3', '4', '5');

  for($i;$i<=count($arr);$i++){
    for($y=$i+1;$y<count($arr); $y++){
       echo ($i+1).'-'.$arr[$y].PHP_EOL;
    }
  }
?>

edited Nov 23 '17 at 10:42

answered Nov 23 '17 at 10:39

Fky

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1
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1-2 , 2-3 , 3-4 , 4-5 , 2-3 , 3-4 , 4-5 , 3-4 , 4-5 , 4-5 This is the output :( – Cristian Longo Nov 23 '17 at 10:41

score -1 · Answer 5 · answered Nov 23 '17 at 10:51

    $players = array('1', '3', '5', '7', '9');

    for($i=0; $i<count($players); $i++) {
        for($j=$i+1; $j<count($players); $j++){
            echo ($players[$i]).' - '.$players[$j].PHP_EOL;
        }
    }

this sould work for any values in the array

score -3 · Answer 6 · answered Nov 23 '17 at 10:41

-3

One foreach loop and a for loop that starts at foreach value +1.

$players =array ('1', '2', '3', '4', '5');

Foreach($players as $player){

    For($i=$player+1; $i<=count($players); $i++){
        Echo $player ."-" .$i."\n";
    }
}

https://3v4l.org/Bunia

answered Nov 23 '17 at 10:41

Andreas

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@MaK that is not part of OPs scope. Leave the scope and requirements to OP. – Andreas Nov 23 '17 at 12:18
@MaK why do you add requirements to the question that the OP has not asked for? Can you answer my question? – Andreas Nov 24 '17 at 04:32
The question state that the OP want all combinations of "an array" so any given array, not that specific array; So how am i adding requirements ? Plus you're not even working with the array values in your inner for loop but only an index based on the array count.. ;/ Your answer is just all tha way wrong PS: I'm not gonna answer any following comments :) – MaK Nov 24 '17 at 09:07
@MaK the question says *i have this array:*. Yes I use the counter index, that is how a for loop works. Also your method is not all that great either. If you think "an array" can be read as any possible array that is not part of requirements, question, scope or example. Then try this in your code please `[1,2,[3],4,5]`. This is also **an array** but just as your it's not part of the requirements, scope, question or example. – Andreas Nov 24 '17 at 09:17

PHP combinations two by two

6 Answers6