Extracting multiple phone number types using regex

Question

My current code finds all cases where '+44' shows up in a website. I want this code to also produce all cases where '0131' occurs. Any help is appreciated, thank you. Code attached below.

phones = re.findall(r'\+44', page.decode())
phones.sort()
print (f'\n [+] {len(phones)} PHONE NUMBERS FOUND:\n')
for phone in phones:
print(phone)

you can use the following regex:r' \+44|0131' instead of your current — AndreyF, Nov 23 '17 at 12:59
@Joe Bloggs next time try to read some material before asking here. — AndreyF, Nov 23 '17 at 13:02

score 0 · Accepted Answer · answered Nov 23 '17 at 13:04

0

It will help you to find numbers of length 10:

import re
re.findall(r"\+44\s+?\d{10}|0131\s+?\d{10}", "This is number  +44 1234567890 and 0131 9090909090323")

answered Nov 23 '17 at 13:04

P.Madhukar

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Extracting multiple phone number types using regex

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