Use Variable as its name and not its content

Question

I have a function that takes 2 inputs, the variable name as a string and the variable itself - it prints both via console.

var variable1 = ["entry1","entry2"];
   function logthis(input1, input2){
    console.log(input1+ "\n " + input2)
    }
    
    logthis("variable1", variable1) ;

I want to be able to use it as logthis(variable1); and get the same result.

How can I reference the variable name (as a string) and not its contents?

eg, console.log(input2.name) will not work

Something like the C+ equivalent of "nameOf(variable1)"

Your input is an array, not an object which have `name` property — Durga, Nov 24 '17 at 12:50
@Satpal 2 - yes i know.I just want to type the variable name once. — platinums, Nov 24 '17 at 15:05
check [this link](https://stackoverflow.com/questions/4602141/variable-name-as-a-string-in-javascript), it may help — user45, Nov 24 '17 at 16:18

score 1 · Answer 1 · answered Nov 24 '17 at 12:53

1

var variable1 = ["entry1","entry2"];
function logthis(input1, input2){
  console.log(input1+ "\n " + input2)
}
    
logthis('variable1', variable1) ;

You are sending the reference. Pass first argument as string.

answered Nov 24 '17 at 12:53

Omaim

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I want to be able to use it as logthis(variable1); – platinums Nov 24 '17 at 16:02

score 0 · Answer 2 · edited Nov 24 '17 at 17:35

0

Try to get your input from the table first

function logthis(inputTable){
       var input1 = inputTable[0];
       var input2 = inputTable[1];

       console.log(input1+ "\n " + input2) // will display "entry1 \n entry2 "
    }
        
    var table1 = ["entry1","entry2"];
    logthis(table1);

edited Nov 24 '17 at 17:35

platinums

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answered Nov 24 '17 at 12:54

andrea06590

1,259
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Use Variable as its name and not its content

2 Answers2