Extract elements from a dict's value

Question

I have the following dict:

In [37]: print(paths)
{'definition': ['dirname', 'basename'],
'condition': ['isdir', 'isfile', 'islink', 'isabs', 'ismount', 'exists', 'lexists'],
'get': ['getatime', 'getctime', 'getmtime', 'getsize'],
'split': ['split', 'splitdrive', 'splitext', 'join', 'normcase'],
'expand': ['expanduser', 'expandvars'],
'same': ['samefile', 'sameopenfile', 'samestat'],
'path': ['abspath', 'commonpath', 'defpath', 'genericpath', 'normpath', 'pathsep', 'realpath', 'relpath']}

The result I want is a path_list:

In [38]: path_list = []
    ...: for v in paths.values():
    ...:     path_list.append(v)
In [42]: print(path_list)
['dirname', 'basename', 'isdir', 'isfile', 'islink', 'isabs', 'ismount', 'exists', 'lexists', 'getatime', 'getctime', 'getmtime', 'getsize', 'split', 'splitdrive', 'splitext', 'join', 'normcase', 'expanduser', 'expandvars', 'samefile', 'sameopenfile', 'samestat', 'abspath', 'commonpath', 'defpath', 'genericpath', 'normpath', 'pathsep', 'realpath', 'relpath']

I attempt to solve the problem with inline codes.

In [43]: [ v for v in paths.values()]
Out[43]:
[['dirname', 'basename'],
 ['isdir', 'isfile', 'islink', 'isabs', 'ismount', 'exists', 'lexists'],
 ['getatime', 'getctime', 'getmtime', 'getsize'],
 ['split', 'splitdrive', 'splitext', 'join', 'normcase'],
 ['expanduser', 'expandvars'],
 ['samefile', 'sameopenfile', 'samestat'],
 ['abspath',
  'commonpath',
  'defpath',
  'genericpath',
  'normpath',
  'pathsep',
  'realpath',
  'relpath']]

It doesn't produce my results.

How to accomplish it?

`itertools.chain.from_iterable` would be the thing to use here... — cs95, Nov 26 '17 at 10:48
https://stackoverflow.com/questions/952914/making-a-flat-list-out-of-list-of-lists-in-python — cs95, Nov 26 '17 at 10:48
It's not like that I can raise a question that has not been answered. @cᴏʟᴅsᴘᴇᴇᴅ — , Nov 26 '17 at 10:56
@Kad what do you mean?! the duplicate addresses exactly how to get from what you've got now to what you want to have in the end! — Antti Haapala -- Слава Україні, Nov 26 '17 at 11:01
`flat_list = [item for sublist in l for item in sublist]` this except now `l` is `paths.values()` — Antti Haapala -- Слава Україні, Nov 26 '17 at 11:04
You’re mistaken in thinking that your question has not been raised or answered before. — cs95, Nov 26 '17 at 11:13
Most, if not all, basic questions have already been asked and answered. Search around. — Ilja Everilä, Nov 26 '17 at 11:14

Extract elements from a dict's value

0 Answers0