Why does the first block compile correctly?

Asked Nov 27 '17 at 15:27

Active Nov 27 '17 at 15:27

Viewed 33 times

Object[] o = new Object[3];  
String[] s = new String[3];

o = s; //compiles
o[0] = new Date();

List<Object> o2 = new ArrayList<>();
List<String> s2 = new ArrayList<>();

o2 = s2; //does not compile

I dont understand why the first block of code o=s; compiles correctly and the assignment of o2=s2; therefor is wrong.

asked Nov 27 '17 at 15:27

user2048767

because an array of `String`s is an array of `Object`s, whereas an List of `String`s is not a list of `Object`s. – Maurice Perry Nov 27 '17 at 15:31
Or, more precisely, a `List` is not a `List – Maurice Perry Nov 27 '17 at 15:32
But note that a `List` is a `List extends Object>`. – Maurice Perry Nov 27 '17 at 15:35

Why does the first block compile correctly?

0 Answers0