C# could not find file 'filepath'

Question

I'm getting the 'cannot be found' error although the file does exist and the path is right. I have tried AudiosInfo.txt.txt and it does not work.

FileStream f = new FileStream("AudiosInfo.txt", FileMode.Open);
StreamReader s = new StreamReader(f);
string l=s.ReadLine();
MessageBox.Show(l);

Next time ask Google. https://stackoverflow.com/q/15653921/974045 — Gibolt, Nov 29 '17 at 00:39
Don't use current directory nor relative file paths, pass the full path to `new FileStream` every time. — Dour High Arch, Nov 29 '17 at 00:45
You mention that *"the path is right"*, yet there is no path shown, only a file name. You should pass the full path and file name to the `FileStream`. — Rufus L, Nov 29 '17 at 01:16
Also, most file operations have been wrapped up nicely in the `File` class. You can just do `MessageBox.Show(File.ReadLines(filePath).FirstOrDefault());` to display the first line of the file located at `filePath` — Rufus L, Nov 29 '17 at 01:22

score 1 · Answer 1 · answered Nov 29 '17 at 04:52

1

When you are using,

FileStream f = new FileStream("AudiosInfo.txt", FileMode.Open);

you have to ensure that, AudiosInfo.txt file must be stored in your solution's \bin\Debug folder.

Otherwise you have to give the full path.

answered Nov 29 '17 at 04:52

Abhilash Ravindran C K

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score 0 · Answer 2 · answered Nov 29 '17 at 00:49

0

This is how you can find the full path: right click on the AudiosInfo.txt file, click on properties, click on the details tab and take a look at the folder path.

answered Nov 29 '17 at 00:49

Susha Naidu

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Actually what is the error? That the txt.file cannot be found? Can you please update the codes with the full path? – Susha Naidu Nov 29 '17 at 01:02

score -1 · Answer 3 · answered Nov 29 '17 at 00:54

Might need to use to find the the path

string filePath = @"C:\MyDir\MySubDir\myfile.ext";
string directoryName;
int i = 0;

while (filePath != null)
{
    directoryName = Path.GetDirectoryName(filePath);
    Console.WriteLine("GetDirectoryName('{0}') returns '{1}'",
        filePath, directoryName);
    filePath = directoryName;
    if (i == 1)
    {
        filePath = directoryName + @"\";  // this will preserve the previous path
    }
    i++;
}
/*

C# could not find file 'filepath'

3 Answers3