JSONDecodeError, when use json.loads in Django

Question

JSONDecodeError, when use json.loads in Django.

POST data

(b'csrfmiddlewaretoken=ikpUI4vMMbYivTby6FUkXRGNXisF6Cgq5eRnYvqoxRoyfAkwiP5GlsBj' b'jVlh3Va4&pergunta%5B1%5D%5Bitem%5D%5B1%5D=&pergunta%5B1%5D%5Bitem%5D%5B2%5D=' b'&pergunta%5B2%5D%5Bitem%5D%5B3%5D=&pergunta%5B2%5D%5Bitem%5D%5B4%5D=&pergunt' b'a%5B2%5D%5Bitem%5D%5B5%5D=&pergunta%5B2%5D%5Bitem%5D%5B6%5D=')

def post(self, request):

    data = json.loads(request.body)
    pprint(data)
    return HttpResponse(data)

Output Error

JSONDecodeError at /

Request Method: POST Request URL: http://localhost:8000/rma/ Django Version: 1.11.7 Exception Type: JSONDecodeError Exception Value:
Expecting value: line 1 column 1 (char 0) Exception Location: /usr/local/Cellar/python3/3.6.2/Frameworks/Python.framework/Versions/3.6/lib/python3.6/json/decoder.py in raw_decode, line 357 Python Executable: /Users/marcelowanderley/Python-Compare/bin/python Python Version: 3.6.2

Possible duplicate of [Trying to parse \`request.body\` from POST in Django](https://stackoverflow.com/questions/29780060/trying-to-parse-request-body-from-post-in-django) — Satendra, Nov 29 '17 at 14:15
Hi, Satendra. Is different. My code is generating an error in executing JSON DECODER. Even then I tried to use the format of this post, without success the same error is shown. Thank you. — marcelo.delta, Nov 29 '17 at 14:22
looks like [For python3 you have to decode body](https://stackoverflow.com/a/35087348/8060120) — Brown Bear, Nov 29 '17 at 14:51

score 0 · Answer 1 · answered Dec 09 '21 at 13:20

0

as @marcelo.delta said and for me worked also...

request.POST.dict()

answered Dec 09 '21 at 13:20

Germano

358
1
2
13

JSONDecodeError, when use json.loads in Django

1 Answers1