How to have the date days later using my format?

Question

the format i need is Y-M-D

similar to 2017-12-01

what i've tried :

import datetime
import time

todaysdate = time.strftime("%Y-%m-%d")
print (todaysdate)
end_date = todaysdate+ datetime.timedelta(days=10)
print (end_date)

The first part should get me today's date then i add 10 date to that date and i should have to outputs 1 in str format the other in date format.

EDIT: i changed my code to the following :

from datetime import datetime,timedelta,date

def next_days(days_value):
    days_from_now = datetime.now() + timedelta(days=days_value)
    return days_from_now

print(next_days(5))

and i got this output 2017-12-06 11:58:45.955056 how do i get 2017-12-06 part only.

Possible duplicate of https://stackoverflow.com/questions/6871016/adding-5-days-to-a-date-in-python — Sumit S Chawla, Dec 01 '17 at 10:16

score 0 · Accepted Answer · answered Dec 01 '17 at 10:09

0

Don't import date and this should work:

from datetime import datetime,timedelta


def next_days(days_value):
    days_from_now = datetime.now() + timedelta(days=days_value)
    return days_from_now.date()

print(next_days(5))

answered Dec 01 '17 at 10:09

RussellB.

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I have used date somewhere else in the code to be able to remove date from the import i need to replace with a function that gets me todays date i have tried datetime.now.date() but it didn't work – Taline Dec 01 '17 at 10:16
The code I wrote will work even if you import `date`. I didn't realize you were using it elsewhere. The code `datetime.now().date()` will also work. – RussellB. Dec 01 '17 at 10:20

How to have the date days later using my format?

1 Answers1