Java type not needed?

Asked Dec 01 '17 at 12:17

Active Dec 01 '17 at 12:17

Viewed 12 times

Map<String, Boolean> map = new HashMap<String, Boolean>();

is equivalent to:

Map<String, Boolean> map = new HashMap();

And I'm honestly not sure why. I get the casting of the HashMap to a Map, what I don't understand is the lack of types provided to the HashMap. Is a Java 8 addition (some kind of compilation inference)?

asked Dec 01 '17 at 12:17

Cody Smith

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Java 7 addition actually. Some sprinkling of syntactic sugar. – Kayaman Dec 01 '17 at 12:18
it's not equivalent, you need to add `new HashMap<>()` – Eugene Dec 01 '17 at 12:19
In the question, i don't see a diamond operator but a raw declaration – davidxxx Dec 01 '17 at 12:19

Java type not needed?

0 Answers0