templated function as a parameter to another templated function

Question

I have an utility function which takes two values and does something on another object if two values meet a certain criteria.

So, the utility function has to take a member function as a std:function and also sometimes as a free flowing function.

class A
{
    public:
    void fun(int a) {}
};

template <typename T>
bool ifSet(T a, T b, std::function<void(T)> f )
{
    if (a == b) return false;
    else return f(b);
}

int main() {
    auto p = std::make_shared<A>(new A);
    std::cout<< ifSet(10, 10, std::bind(A::fun, p, std::placeholders::_1));

The above code is my dummy implementation, but doesn't work. Can someone suggest me a better code ?

"_but doesn't work._" Such statement is meaningless - please explain what, **exactly**, doesn't work in such implementation. — Algirdas Preidžius, Dec 01 '17 at 16:21
if `f()` return `void` and `ifSet` return a `bool`, with `return f(b);` you have a problem — max66, Dec 01 '17 at 16:22
Related: https://stackoverflow.com/questions/17131768/how-to-directly-bind-a-member-function-to-an-stdfunction-in-visual-studio-11 — Rakete1111, Dec 01 '17 at 16:23

score 2 · Answer 1 · answered Dec 01 '17 at 16:26

2

Your

std::function<void(T)> f

return a void and you use it as return for bool ifSet() function

answered Dec 01 '17 at 16:26

Moia

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templated function as a parameter to another templated function

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