PHP for loop throws undefined offset warning

Question

When I run the following code, I get exactly that output that I need.

$array_items = count($links);
for ($i = 0; $i <= $array_items; $i++) {
    echo $links[$i]->title;
}

However, I get 2 notices:

Notice: Undefined offset: 2 in C:\xampp\htdocs...

Notice: Trying to get property of non-object in C:\xampp\htdocs...

I guess that's because $links returns an array and inside that array there is an object.

How can I fix it?

If `$links` is an array, why don't you just use a `foreach`? — azeós, Dec 03 '17 at 03:11

score 1 · Accepted Answer · answered Dec 03 '17 at 03:09

1

You need to check only if $i is lower than the count because the index start form 0 and the count give you back the total items (+1)

$array_items = count($links);
for ($i = 0; $i < $array_items; $i++) {
    echo $links[$i]->title;
}

answered Dec 03 '17 at 03:09

Shibi

Very helpful! Thank you! – Reza Saadati Dec 03 '17 at 03:13
@RezaSaadati if their solution got rid of the warnings for you, could you click on the check mark to select it as the correct answer? – vqdave Dec 03 '17 at 03:18
Sure, I just had to wait for it. Because you always have to wait about 10 minutes ;) – Reza Saadati Dec 03 '17 at 03:31

1 Answers1