From GNU bash manual https://www.gnu.org/software/bash/manual/html_node/Shell-Parameter-Expansion.html
${parameter#word}
${parameter##word}
The word is expanded to produce a pattern just as in filename expansion (see Filename Expansion). If the pattern matches the beginning of the expanded value of parameter, then the result of the expansion is the expanded value of parameter with the shortest matching pattern (the ‘#’ case) or the longest matching pattern (the ‘##’ case) deleted. If parameter is ‘@’ or ‘’, the pattern removal operation is applied to each positional parameter in turn, and the expansion is the resultant list. If parameter is an array variable subscripted with ‘@’ or ‘’, the pattern removal operation is applied to each member of the array in turn, and the expansion is the resultant list.
Simple explantion
Assume, parameter, PWD = /home/abc/pqr
Word is the pattern that matches */
. Which means /home/abc/
. Since pqr
doesnot have a trailing /
, pqr
doesnot match that pattern.
From GNU bash manual,
the longest matching pattern (the ‘##’ case) deleted
##
means delete the longest matching pattern from parameter. Which means remove /home/abc/
from /home/abc/pqr
.
Which gives you pqr
PS: There are no dumb questions