How to display when data more than array in c++?

Question

this my program...

{
    char name[5];
    cout << "NPM : ";
    cin >> name;
    cout << "  name: " << name <<endl;
}

make the display name, birth date, with the provisions of each letter can not be more, if more then error. use array function !! how to input data if more array notice error..?

I'm voting to close this question as off-topic because SO is not free code writing service — Slava, Dec 05 '17 at 14:45
If you don't want to use `std::string`, consider using `std::vector`. — Thomas Matthews, Dec 05 '17 at 14:45
@febriankusuma I'm pretty sure you missed the point of the question. Why are you using a fixed array `char[5]` instead of a resizeable string (i.e., `std::string`) if you'll need to support an unknown max number of characters? — James Adkison, Dec 05 '17 at 14:48
@febriankusuma I don't see how that relates to the comments, but if you said so, related reading: [Why is “using namespace std” considered bad practice?](https://stackoverflow.com/questions/1452721/why-is-using-namespace-std-considered-bad-practice). — Algirdas Preidžius, Dec 05 '17 at 14:48

Insax · Answer 1 · 2017-12-05T14:56:19.100

2

{
   char name[5];
   cout << "NPM : ";
   cin.getline(name, 5);
   cout << "   name: " << name << endl;
}

Would be possible approach if you HAVE to use char arrays.

The maxlenght for the String itself will be 4 characters long, because char[4] will be a Nullbyte ( '\0' )

edited Dec 05 '17 at 14:56

answered Dec 05 '17 at 14:47

Insax

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but... why? it's basic C/C++ – Iosif Murariu Dec 05 '17 at 14:48
I have no clue, maybe he doesn't know that std::string exists or he's doin it for school... – Insax Dec 05 '17 at 14:50
Note that the input will be truncated to 4 chars followed by the terminating '\0' – Killzone Kid Dec 05 '17 at 14:52
yeah, but answering such a basic question I don't think it's gonna help him understand the logic behind it.. – Iosif Murariu Dec 05 '17 at 14:52
ok, thank all for giving answer.. – febrian kusuma Dec 05 '17 at 14:52
@IosifMurariu It's basic c++, but not basic C. It's not C at all. – François Andrieux Dec 05 '17 at 14:54
@IosifMurariu I wouldn't call it C at all – UKMonkey Dec 05 '17 at 14:54
1

Sometimes I am surprised how useless answers to useless questions are upvoted. – Slava Dec 05 '17 at 14:55
yeah, yeah, i know. I wouldn't call it Java either. – Iosif Murariu Dec 05 '17 at 14:57
Despite you are wrong about which symbol would be 0, how is this answer related to the question? – Slava Dec 05 '17 at 14:57
And why am I wrong about the nullbyte? And its exactly the answer to the question, he wants to know how to prevent a crash if you enter a string larger than 4 characters – Insax Dec 05 '17 at 14:59

How to display when data more than array in c++?

1 Answers1