Convert array to conditional php

Question

I have and array, and I want to convert it into an if conditional.

$array = ['check 1', 'check 2', 'check 3'];

I want the final result to work like this:

if ($var == 'check 1' || $var == 'check 2' || $var == 'check 3') {
    // Do here.
}

I don't have any inspiration, I already searched for convert array to if condition but I couldn't find anything.

How can I convert the array into an if conditional?

`if (in_array($var, $array) || in_array($var1, $array)){ //do something }` — urfusion, Dec 07 '17 at 11:02
Where is the [array](http://php.net/manual/en/language.types.array.php)? I cannot see any [array](http://php.net/manual/en/function.array.php) in the code you posted. — axiac, Dec 07 '17 at 11:17
@axiac `$array = ( 'check 1', 'check 2', 'check 3' );` ? then the code below is just an example wit normal var, but he wud like to achieve same using an array — Masivuye Cokile, Dec 07 '17 at 11:22
@MasivuyeCokile `$array` in this code is not an [array](http://php.net/manual/en/language.types.array.php). The code doesn't even compile, it reports a parsing error at the first comma. So, I'm asking again, where is the [array](http://php.net/manual/en/function.array.php)? — axiac, Dec 07 '17 at 11:45
A relevant/inspirational reference: https://stackoverflow.com/questions/13483219/what-is-faster-in-array-or-isset — mickmackusa, Dec 07 '17 at 14:18

Alive to die - Anant · Accepted Answer · 2017-12-07T11:44:57.417

Instead of multiple || (OR) conditions use in_array()

if (in_array($var, $array)) {
    // do here
}

Output:-https://eval.in/914346

If you want to check multiple variables against array then do like this:-

if (in_array($var, $array) || in_array($var1, $array)){ 
  //do here
}

Output:- https://eval.in/914351

Note:- If you can clarify more about all your variables and what conditions you want for all those variables, you will get more accurate answer

score 1 · Answer 2 · edited Dec 07 '17 at 11:04

1

Loop through array and check in_array like this:

$array = ( 'check 1', 'check 2', 'check 3' );

    foreach($array as $k => $v)
    {
        $flag = "false";
        if(in_array($v,$array))
        {
            $flag = "true";
        }
    }

So from above code, is any of the value exist in array, the variable $flag will have string value "true".

edited Dec 07 '17 at 11:04

Masivuye Cokile

4,754
3
19
34

answered Dec 07 '17 at 11:03

Himanshu Upadhyay

6,558
1
20
33

score 1 · Answer 3 · edited Dec 07 '17 at 11:44

1

<?php

$array = array( "mango", "grapes","apple");
//let you have to find apple

if(in_array('masngo',$array) || in_array('mango',$array)){
    echo "FIND";
    //OR WHATEVER YOU WANT TO DO
}else{
    echo "Not Found";
}

Try to run HERE

edited Dec 07 '17 at 11:44

Alive to die - Anant

70,531
10
51
98

answered Dec 07 '17 at 11:04

TarangP

2,711
5
20
41

This won't be a generic solution. – Himanshu Upadhyay Dec 07 '17 at 11:14

Convert array to conditional php

3 Answers3