Is there a setting on JSON Covert to throw any error if json is malformed

Question

I have the following json which is malformed, which has missing property value, I want JSON.Convert to throw an error while deserializing, but instead phoneNumber is replaced with null when deserialize to strongly typed Object Person, and with dynamic type the value of phoneNumber is replaced with {}, I have tried various JsonSerializerSettings but doesn't seem to help throw an error, is there a way to do this

var json=    {
      "firstName": "joe",
      "lastName": "doe",
      "phoneNumber": ,
      "email": "joe.doe@test.com"
    }
JsonConvert.DeserializeObject<Person>(json);
JsonConvert.DeserializeObject<Dynamic>(json);

@Ryan yeah if tried in other libraries in javascript or python, it just throws an error which is good — inan, Dec 08 '17 at 15:49
Check this out: https://stackoverflow.com/questions/22683040/how-to-check-all-properties-of-an-object-whether-null-or-empty (check after deserialization) — LocEngineer, Dec 08 '17 at 15:51

Gerrie Pretorius · Answer 1 · 2017-12-08T15:55:01.180

0

This might be a bit of a work around, but you can mark it with an attribute that a value is required. Which migh or might not work for you depending on your exact case:

public class Videogame
{
    [JsonProperty(Required = Required.Always)]
    public string Name { get; set; }

    [JsonProperty(Required = Required.AllowNull)]
    public DateTime? ReleaseDate { get; set; }
}

edited Dec 08 '17 at 15:55

answered Dec 08 '17 at 15:52

Gerrie Pretorius

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I preferred using dynamic based on my use case, but let me try with this attribute – inan Dec 08 '17 at 15:54
Actually in my use case the property is not a required field, so adding this attribute is will not help – inan Dec 08 '17 at 15:56
@inan It might still help if i interpret the documentation correctly: Metadata states the following for Required.Always: "The property must be defined in JSON and cannot be a null value." – Gerrie Pretorius Dec 08 '17 at 15:58
oh wait nevermind... it can be a null value in your case – Gerrie Pretorius Dec 08 '17 at 15:59

Is there a setting on JSON Covert to throw any error if json is malformed

1 Answers1