Search to extract words inside single quotes or double quotes from a sentence. in javascript

Question

Example :work "work & work

Result : ["work & work"]

Example : Exercise is "good" for "health" Result : ["good", "health"]

I wanted them in javascript

Answer 1

This answer is what you're looking for, including the snippet below with explanation for quick reference.

(["'])(?:(?=(\\?))\2.)*?\1

As an example using Javascript:

function getWordsBetweenQuotes(str) {
    return str.match(/(["'])(?:(?=(\\?))\2.)*?\1/g);
}

([""']) match a quote; ((?=(\?))\2.) if backslash exists, gobble it, and whether or not that happens, match a character; *? match many times (non-greedily, as to not eat the closing quote); \1 match the same quote that was use for opening.

Answer 2

You can do

function getResult(str){
    return str.split('"').filter((e, i) => (i&1))
}

console.log(getResult('work "work & work'));
console.log(getResult('Exercise is "good" for "health"'));

Answer 3

Maybe a regexp like this will work:

str.match(/\w+|"[^"]+"/g)

Answer 4

var words = 'Exercise is "good" for "health"'.match(/(?<=")([\w]*?)(?=")/g);

console.log(words)