How to replace a string by using UNIX command?

Question

How to replace a string by number of times other/itself string?

e.g. UNIX is good. replace UNIX by 4 times O/p : UNIXUNIXUNIXUNIX is good.

How to do similar way n times?.

Possible duplicate of [Multiplying strings in bash script](https://stackoverflow.com/questions/38868665/multiplying-strings-in-bash-script) — Benjamin W., Dec 12 '17 at 18:04

score 1 · Answer 1 · answered Dec 12 '17 at 19:40

1

This one is good too

echo 'UNIX is good.' | sed 's/[^ ]*/&&&&/'

answered Dec 12 '17 at 19:40

ctac_

1

If it's for n times? Instead just 4 times. – anilhr2learn Dec 12 '17 at 20:01

score 0 · Answer 2 · answered Dec 12 '17 at 17:52

With this test file:

$ cat File
UNIX is good.

Try:

$ awk -v n=4 '{for (i=1;i<n;i++)sub(/(UNIX)+/, "&UNIX")} 1' File
UNIXUNIXUNIXUNIX is good.

Or:

$ s='UNIX is good.'
$ n=4; for ((i=1;i<n;i++)); do s=${s/UNIX/UNIXUNIX}; done; echo "$s"
UNIXUNIXUNIXUNIX is good.

score 0 · Answer 3 · answered Dec 15 '17 at 12:34

0

a perl script:

#!/usr/local/bin/perl
use strict;
use warnings;
my $n= 4;
print 'UNIX'x$n . ' is good';

answered Dec 15 '17 at 12:34

GAD3R

3 Answers3