Create output files from lines of loop?

Question

I have list like this:

test_list = ['test1','test2','test3']

I want to create from each element of the array a separate txt file and write content to that like in below:

for test in test_list:
    print (test, outfile=testdir/test + '.txt')

Obviously this code doesn't work. I would like to know how can I do this?

`outfile` (which should be `file`) must be a Python's _file object_. __Please read the docs before asking questions and even attempting to write code.__ Quote from `help(print)`: "file: a _file-like object_ (stream); defaults to the current sys.stdout" — ForceBru, Dec 12 '17 at 17:49
@ForceBru. I know. just wanted to show that what I need :). But I don't know how to create this — Qaqa Leveo, Dec 12 '17 at 17:51
I don't know how to open multiple file. Because this was just example it can be 10000 files — Qaqa Leveo, Dec 12 '17 at 17:53
Are you sure that you really want to keep 10000 files opened *at the same time*??? — Serge Ballesta, Dec 12 '17 at 17:58
Possible duplicate of [Directing print output to a .txt file in Python 3](https://stackoverflow.com/questions/36571560/directing-print-output-to-a-txt-file-in-python-3) — mkrieger1, Dec 12 '17 at 17:59

user2614596 · Answer 1 · 2017-12-12T18:17:07.800

1

test_list = ['test1','test2','test3']
for test in test_list:
   with open('{}.txt'.format(test),'w+') as f:
      f.write(test)

edited Dec 12 '17 at 18:17

answered Dec 12 '17 at 18:00

user2614596

This is the correct method for Python 3.x as per the docs: https://docs.python.org/3/tutorial/inputoutput.html#reading-and-writing-files – dijksterhuis Dec 12 '17 at 18:04
1

@ForceBru it will if you change `wb` to `w+`. I was talking about the use of `with open` in terms of correct methods. – dijksterhuis Dec 12 '17 at 18:15

score 0 · Accepted Answer · answered Dec 12 '17 at 17:55

0

This will help you

test_list = ['test1','test2','test3']

for test in test_list:
    f = open('{}.txt'.format(test),'wb') #
    f.write(test)
    f.close()

answered Dec 12 '17 at 17:55

babygame0ver

It won't on Python 3.x: `TypeError: a bytes-like object is required, not 'str'` – ForceBru Dec 12 '17 at 17:56
yeah , but he has mentioned 2.7 also – babygame0ver Dec 12 '17 at 17:57
Which was definitely a mistake as `print(stuff, arg=stuff)` works in Python 3.x only. – ForceBru Dec 12 '17 at 17:57
1

@ForceBru not necessarily, `from __future__ import print_function` – juanpa.arrivillaga Dec 12 '17 at 18:07
@juanpa.arrivillaga, however, the OP's code doesn't have this line. Tagging with both Python 3.x and Python 2.7 is strange anyway. 2 out of 3 answers here don't work in Python 3.x, so using both tags is clearly confusing. – ForceBru Dec 12 '17 at 18:12
@ForceBru Oh, I agree, the OP hasn't adequately specified their situation. – juanpa.arrivillaga Dec 12 '17 at 18:13
if he has accepted the answer then , it is definitely 2.7 – babygame0ver Dec 12 '17 at 18:16
@babygame0ver or it was the first one they saw (pattern works in 2.x and 3.x) – dijksterhuis Dec 12 '17 at 18:20

sanjusci · Answer 3 · 2017-12-12T18:24:30.427

-1

I thing it will help you.

test_list = ['test1','test2','test3']
for l in test_list:
    with open('{}.txt'.format(l), 'a') as s:
         s.write(l)

If you want to write something you can use same as above.

edited Dec 12 '17 at 18:24

answered Dec 12 '17 at 18:09

sanjusci

Doesn't work as `s.write` returns an _integer_: `AttributeError: 'int' object has no attribute 'close'`. – ForceBru Dec 12 '17 at 18:15
If you are using the `with open` syntax, you shouldn't need to call the `close()` method afterwards. See @user2614596 answer above – dijksterhuis Dec 12 '17 at 18:18
Python 2.7.12 (default, Nov 19 2016, 06:48:10) [GCC 5.4.0 20160609] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> test_list = ['test1','test2','test3'] >>> for l in test_list: ... with open('{}.txt'.format(l), 'a') as s: ... s.write(l) ... >>> >>> s >>> not given any error please check once on version 2.7 V – sanjusci Jan 25 '18 at 06:55

3 Answers3