Get the date a year from today in dd/mm/yyyy format in python

Question

I am trying to get a date an year from todays date into a variable. Below is my code.

import time
import datetime
today = time.strftime("%m/%d/%Y")
today_format = datetime.datetime.strptime(today, "%m/%d/%Y")
print (today_format)
exp_date = str(today_format + datetime.timedelta(days=365)).split(" ")
exp = exp_date[0]
print (exp)`

Above code prints:

2017-12-14 00:00:00
2018-12-14

Any idea how to get it to print 12/14/2018??

for subtracting any year, month or etc. take a look at here. https://stackoverflow.com/questions/5871168/how-can-i-subtract-or-add-100-years-to-a-datetime-field-in-the-database-in-djang — Moher, Dec 14 '17 at 23:02
I'd use years=1 rather than days=365, it'll handle leap years better. — Octopus, Dec 14 '17 at 23:15
@Octopus you can't using `datetime.timedelta`. It only accepts days, seconds, microseconds, milliseconds, minutes, hours, weeks arguments — Loïc G., Dec 14 '17 at 23:19

Moher · Accepted Answer · 2017-12-15T11:55:49.110

8

using dateutil.relativedelta package, you can do:

import datetime
from dateutil.relativedelta import relativedelta

one_year_from_now = datetime.datetime.now() + relativedelta(years=1)
date_formated = one_year_from_now.strftime("%d/%m/%Y")
print date_formated

how to install dateutil package

edited Dec 15 '17 at 11:55

answered Dec 14 '17 at 23:06

Moher

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"a year from today" typically means one year into the future, not the past. – jarmod Dec 15 '17 at 00:04

Ibraheem Ahmed · Answer 2 · 2017-12-16T20:08:25.393

4

Try using the datetime module:

datetime.datetime.today().strftime('%m/%d/%Y')

Prints:

'12/14/2017'

edited Dec 16 '17 at 20:08

answered Dec 14 '17 at 23:08

Ibraheem Ahmed

11,652
2
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I need the output as a date a year from today in MM/DD/YYYY format and not MM-DD-YYYY format. UI throws an error with MM-DD-YYYY format. – Sel_Python Dec 15 '17 at 18:35
Use this code: `datetime.datetime.today().strftime('%m/%d/%Y')` @Sel_Python – Ibraheem Ahmed Dec 15 '17 at 21:30

score 0 · Answer 3 · answered Dec 16 '17 at 20:12

0

If you use pandas

import pandas as pd
pd.to_datetime('now') + pd.offsets.DateOffset(years=1)

answered Dec 16 '17 at 20:12

Anton vBR

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5
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Keelan Butler · Answer 4 · 2023-03-16T10:30:24.933

Late to the party for this one, but had the same issue and this is my solution:

date1 = datetime.today().strftime('%Y-%m-%d')
def monthreduct(date):
    
    def under10(date):
        if int(date[1]) < 10:
               date[1] = f'0{date[1]}'
               
    date = date.split('-')    
    date[1] = int(date[1])  
    if date[1] <= 1:
        date[0] = int(date[0]) - 1
        date[0] = str(date[0])
        date[1] = str(12)
    else:
        date[1] = int(date[1]) - 1
    date[1] = str(date[1])
    under10(date)
    return "-".join(date)

This will allow a date, for example 12-09-2030 to be adjusted to 12-08-2030.

Get the date a year from today in dd/mm/yyyy format in python

4 Answers4