Simple if statement on python interpreter

Question

Environment:

Fedora 27 (GNU/Linux)
terminal
python3.6.3

I am having problems running this simple lines of code in the python interpreter, this is an only if statement or alone if statement.

n = 5
if n == 4:
    print('n=4')
print('done')

This must print the word "done", but what am I doing wrong?

try `print 'done'`, maybe you are running it on an older version — Ibo, Dec 16 '17 at 00:44
The brackets are irrelevant. In Python2 `print('done')` is `print ('done')` which is `print 'done'`. — t.m.adam, Dec 16 '17 at 00:51
The `...` is a hint from the interpreter that it expects you to be in an indented block. Entering a non-indented statement in that context is an error. — John Gordon, Dec 16 '17 at 00:58

Brett Beatty · Accepted Answer · 2017-12-16T01:04:39.870

18

The interpreter gives you a line after blocks to leave blank for the interpreter to know your block is over (or to put an else, etc.). Putting something there makes it freak out. Just leave it that line blank and wait for the next >>> before your print('done').

>>> n = 5
>>> if n == 4:
...    print('n=4')
...
>>> print('done')
done

edited Dec 16 '17 at 01:04

answered Dec 16 '17 at 00:51

Brett Beatty

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well , That makes a lot of sense. My error was the last print , that in reality should be placed in the next _primary prompt_ (>>>). – christianbueno.1 Dec 16 '17 at 01:12

Simple if statement on python interpreter

1 Answers1