Didn't receive Value from ajax to PHP file

Question

At first here is my code:

HTML with Javascript:

function getValues(){
    var filter;
    $.ajax({
            type: "POST",
            url: "myphpfile.PHP?action=sek",
            data: "id=1",
            async: false,
            success: function(ret){
                    filter = ret;
                }
        });
    console.log(filter);

PHP myphpfile.php:

if(isset($_GET['action'])){
    print myfunction($_GET['action'],$_GET['id']);
}

My problem: When I try to print the result out with console.log, the whole myphpfile.php is printed. As I know, that means that no values reached the HTML file. But Why?

The function "myfunction" have results, i have tried it first. This function returns an array. ( I can't show this function here)

I don't get it what i'm doing wrong, Please have a look, It drive me crazy.

Thanks in advance!

To start with you are making a `post` request with AJAX then expecting a `get` request in your function! — drmonkeyninja, Dec 19 '17 at 09:26
possible duplicate of https://stackoverflow.com/questions/2013728/passing-javascript-array-to-php-through-jquery-ajax — Edwin, Dec 19 '17 at 09:27

TarangP · Answer 1 · 2017-12-19T09:35:29.097

0

Change PHP File Request

if(isset($_GET['action'])){
    print myfunction($_GET['action'],$_GET['id']);
}

Also You can use $_REQUEST.

edited Dec 19 '17 at 09:35

answered Dec 19 '17 at 09:27

TarangP

2,711
5
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Kancho Iliev · Answer 2 · 2017-12-19T09:34:27.413

0

First in Javascript:

function getValues(){
    var filter;
    $.ajax({
            type: "POST",
            url: "myphpfile.PHP?action=sek",
            data: { id: 1 },
            async: false,
            success: function(ret){
                    filter = ret;
                }
        });
    console.log(filter);

Afterthat you have to obtain id by $_POST['id']

edited Dec 19 '17 at 09:34

answered Dec 19 '17 at 09:28

Kancho Iliev

701
5
13

1

` $_POS['id'] ` Changes to `$_POST['id]` – TarangP Dec 19 '17 at 09:33
Yes. Done, Thanks! – Kancho Iliev Dec 19 '17 at 09:35

score 0 · Accepted Answer · answered Dec 19 '17 at 09:37

action is in the $_GET super global and id is in the $_POST super global.

PHP:

if(isset($_GET['action'])){
    print myfunction($_GET['action'],$_POST['id']);
}

Also, you need to pass an object to your data parameter, not a string:

JS:

$.ajax({
    type: "POST",
    url: "myphpfile.PHP?action=sek",
    data: {id: "1"},
    async: false,
    success: function(ret){
            filter = ret;
        }
});

Didn't receive Value from ajax to PHP file

3 Answers3