Search in and return a json object in JS

Question

I have a JSON object with user information, its a large array of thousand of users an example of one is:

[ { 
    "FirstName" : "Joe",
    "LastName" : "Doe",
    "Address" : "123 Main Street"
   }
]

I want to be able to search in this json array based on first and last name and return the object that matches.

Then iterate over that array and find that one that matches? Which problem do you have? — Jonas Wilms, Dec 20 '17 at 18:40
Possible duplicate of [Find a value in an array of objects in Javascript](https://stackoverflow.com/questions/12462318/find-a-value-in-an-array-of-objects-in-javascript) — James, Dec 20 '17 at 18:53

score 5 · Answer 1 · edited Dec 12 '20 at 04:30

5

Take a look at es6-feature

There're 2 method in array:

find: array.find(x => x.firstName === 'Joe' && x.LastName === 'Doe' ): returns single matche which means exactly 1 object or null.
filter: array.filter(x => x.firstName === 'Joe' && x.LastName === 'Doe' ) returns array of matches.

edited Dec 12 '20 at 04:30

Rocard Fonji

answered Dec 20 '17 at 18:37

deathangel908

Because of `x.firstName = 'Joe'` everybody will be called Joe X afterwards. – JJWesterkamp Dec 20 '17 at 18:45

score 1 · Answer 2 · answered Dec 20 '17 at 18:37

1

you can use the filter function on array

var result = largeJsonArray.filter(function(item){
   return item.FirstName === 'Jhon' && item.LastName === 'Doe'
});

result is a list of element that match the criteria

take a look to the documentation

answered Dec 20 '17 at 18:37

stalin

var foundItem = userData.filter(user => { return user.FirstName === userParts[0] && user.LastName === userParts[1]; }); I am getting error 'filter is not a function' – Pacman Dec 20 '17 at 18:44
filter only exists on javascript arrays, check if userData is an array – stalin Dec 20 '17 at 20:32

score 1 · Accepted Answer · answered Dec 20 '17 at 18:39

1

You can parse json and use Array.prototype.find:

const arr = JSON.parse("your json")

const result = arr.find(elem => elem.FirstName === "Joe")

answered Dec 20 '17 at 18:39

Sergo Pasoevi

3 Answers3