I would like to select the "top most" entry for each row with a duplicated column value.
Performing the following query -
SELECT *
FROM shop
ORDER BY shop.start_date DESC, shop.created_date DESC;
I get the result set -
+--------+---------+------------+--------------+
| row_id | shop_id | start_date | created_date |
+--------+---------+------------+--------------+
| 1 | 1 | 2017-02-01 | 2017-01-01 |
| 2 | 1 | 2017-01-01 | 2017-02-01 |
| 3 | 2 | 2017-01-01 | 2017-07-01 |
| 4 | 2 | 2017-01-01 | 2017-01-01 |
+--------+---------+------------+--------------+
Can I modify the SELECT
so that I only get back the "top rows" for each unique shop_id -- in this case, row_id
s 1 and 3. There can be 1..n number of rows with the same shop_id
.
Similarly, if my query above returned the following order, I'd want to only SELECT
row_id
s 1 and 4 since those would be the "top most" entries each shop_id
.
+--------+---------+------------+--------------+
| row_id | shop_id | start_date | created_date |
+--------+---------+------------+--------------+
| 1 | 1 | 2017-02-01 | 2017-01-01 |
| 2 | 1 | 2017-01-01 | 2017-02-01 |
| 4 | 2 | 2017-01-01 | 2017-07-01 |
| 3 | 2 | 2017-01-01 | 2017-01-01 |
+--------+---------+------------+--------------+