Executing as jar says "System cannot find the properties file specified"

Question

I have a gradle project with app.properties file present in the src/main/resources folder.

When i am trying to execute the project using jar, it says not able to read the app.properties file specified.

Below is the code to read the properties file :

  Properties properties = new Properties();  
  File file = new File("src/main/resources/app.properties");
  FileInputStream inputStream = new FileInputStream(file);
  properties.load(inputStream);

I am using below command to run the jar :

Java -jar App.jar

Any help on this issue will be appreciated.

where is your properties file? in your jar file? somewhere exterior to it? — Stultuske, Dec 21 '17 at 10:05
its in src.main/resources folder. In local it works fine. When i create a jar and execute it throws this exception. — Yathish Manjunath, Dec 21 '17 at 10:17
that's because now you're trying to load the file from within the jar. Check this thread: https://stackoverflow.com/questions/2815404/load-properties-file-in-jar — Stultuske, Dec 21 '17 at 10:18
'It' says *exactly* what? NB Your `src` directory won't be there at runtime. — user207421, Dec 21 '17 at 10:18

score 2 · Answer 1 · answered Dec 21 '17 at 10:13

2

Try with getSystemResourceAsStream

 try (InputStream inputStream = ClassLoader.getSystemResourceAsStream("app.properties"))

answered Dec 21 '17 at 10:13

NSKBpro

373
1
14

Prodian · Answer 2 · 2017-12-21T10:20:30.067

Most probably, when you make that project jar, the destination of the run file is changed. My English is not good, I know but I can suggest you that:

Make :

File file = new File("app.properties");

and please be sure that, App.jar and app.properties are in the same folder.

Have a good day :)

Another solution,

FileReader fileReader = new FileReader("app.properties");
 BufferedReader bufferedReader = new BufferedReader(fileReader);
 while((line = bufferedReader.readLine()) != null) {
        if(line.contains(/* WHAT YOU WANT*/)){
               // DO THE PROCESS    
         }  
  }

 bufferedReader.close();

You can try this too as an alternative.

@YathishManjunath I added second solution, you can try this too. — Prodian, Dec 21 '17 at 10:20

Vikash Kumar · Answer 3 · 2020-11-25T14:49:56.193

For someone still facing this problem:

public static void main(String[]  args){  
        InputStream is=MainMethod.class.getClassLoader().getResourceAsStream("xy.xml");
        Properties properties = new Properties();
        properties.loadFromXML(is);
        //xy.properties or xy.xml
        String somedata = properties.getProperty("somedata");
    }

xy.xml should be packaged along with the jar. Its working for me in both windows and lynux server. This works for normal java program as well.

Executing as jar says "System cannot find the properties file specified"

3 Answers3

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