I want to do:
int a = 255;
cout << a;
and have it show FF in the output, how would I do this?
Use:
#include <iostream>
...
std::cout << std::hex << a;
There are many other options to control the exact formatting of the output number, such as leading zeros and upper/lower case.
To manipulate the stream to print in hexadecimal use the hex
manipulator:
cout << hex << a;
By default the hexadecimal characters are output in lowercase. To change it to uppercase use the uppercase
manipulator:
cout << hex << uppercase << a;
To later change the output back to lowercase, use the nouppercase
manipulator:
cout << nouppercase << b;
std::hex
is defined in <ios>
which is included by <iostream>
. But to use things like std::setprecision/std::setw/std::setfill
/etc you have to include <iomanip>
.
I understand this isn't what OP asked for, but I still think it is worth to point out how to do it with printf. I almost always prefer using it over std::cout (even with no previous C background).
printf("%.2X", a);
'2' defines the precision, 'X' or 'x' defines case.
std::hex
gets you the hex formatting, but it is a stateful option, meaning you need to save and restore state or it will impact all future output.
Naively switching back to std::dec
is only good if that's where the flags were before, which may not be the case, particularly if you're writing a library.
#include <iostream>
#include <ios>
...
std::ios_base::fmtflags f( cout.flags() ); // save flags state
std::cout << std::hex << a;
cout.flags( f ); // restore flags state
This combines Greg Hewgill's answer and info from another question.
There are different kinds of flags & masks you can use as well. Please refer http://www.cplusplus.com/reference/iostream/ios_base/setf/ for more information.
#include <iostream>
using namespace std;
int main()
{
int num = 255;
cout.setf(ios::hex, ios::basefield);
cout << "Hex: " << num << endl;
cout.unsetf(ios::hex);
cout << "Original format: " << num << endl;
return 0;
}
C++20 std::format
This is now the cleanest method in my opinion, as it does not pollute std::cout
state with std::hex
:
main.cpp
#include <format>
#include <string>
int main() {
std::cout << std::format("{:x} {:#x} {}\n", 16, 17, 18);
}
Expected output:
10 0x11 18
Not yet implemented on GCC 10.0.1, Ubuntu 20.04.
But the awesome library that became C++20 and should be the same worked once installed on Ubuntu 22.04 with:
sudo apt install libfmt-dev
or:
git clone https://github.com/fmtlib/fmt
cd fmt
git checkout 061e364b25b5e5ca7cf50dd25282892922375ddc
mkdir build
cmake ..
sudo make install
main2.cpp
#include <fmt/core.h>
#include <iostream>
int main() {
std::cout << fmt::format("{:x} {:#x} {}\n", 16, 17, 18);
}
Compile and run:
g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main2.out main2.cpp -lfmt
./main2.out
Documented at:
More info at: std::string formatting like sprintf
Pre-C++20: cleanly print and restore std::cout
to previous state
main.cpp
#include <iostream>
#include <string>
int main() {
std::ios oldState(nullptr);
oldState.copyfmt(std::cout);
std::cout << std::hex;
std::cout << 16 << std::endl;
std::cout.copyfmt(oldState);
std::cout << 17 << std::endl;
}
Compile and run:
g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main.out main.cpp
./main.out
Output:
10
17
More details: Restore the state of std::cout after manipulating it
Tested on GCC 10.0.1, Ubuntu 20.04.
Use std::uppercase
and std::hex
to format integer variable a
to be displayed in hexadecimal format.
#include <iostream>
int main() {
int a = 255;
// Formatting Integer
std::cout << std::uppercase << std::hex << a << std::endl; // Output: FF
std::cout << std::showbase << std::hex << a << std::endl; // Output: 0XFF
std::cout << std::nouppercase << std::showbase << std::hex << a << std::endl; // Output: 0xff
return 0;
}
How are you!
#include <iostream>
#include <iomanip>
unsigned char arr[] = {4, 85, 250, 206};
for (const auto & elem : arr) {
std::cout << std::setfill('0')
<< std::setw(2)
<< std::uppercase
<< std::hex
<< (0xFF & elem)
<< " ";
}