Say you unzip a file called file123.zip with zipfile.ZipFile, which yields an unzipped file saved to a known path. However, this unzipped file has a completely random name. How do you determine this completely random filename? Or is there some way to control what the name of the unzipped file is?
I am trying to implement this in python.
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creyD
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iknowfrench
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Doesn't the unzipped file have the same name as the zipped one? – DavidG Dec 22 '17 at 09:15
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No, it does not. And what I meant to say was that the unzipped file name is completely arbitrary and not random, as @mhawke said below – iknowfrench Dec 22 '17 at 18:24
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@iknowfrench: in that case, is there something about my answer that doesn't solve your problem? You can choose your own file name, and the file names are available in `namelist()`. – mhawke Dec 23 '17 at 00:32
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@mhawke absolutely not, your code solved my problem perfectly! – iknowfrench Dec 24 '17 at 03:35
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By "random" I assume that you mean that the files are named arbitrarily.
You can use ZipFile.read() which unzips the file and returns its contents as a string of bytes. You can then write that string to a named file of your choice.
from zipfile import ZipFile
with ZipFile('file123.zip') as zf:
for i, name in enumerate(zf.namelist()):
with open('outfile_{}'.format(i), 'wb') as f:
f.write(zf.read(name))
This will write each file from the archive to a file named output_n in the current directory. The names of the files contained in the archive are obtained with ZipFile.namelist(). I've used enumerate() as a simple method of generating the file names, however, you could substitute that with whatever naming scheme you require.
mhawke
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If the filename is completely random you can first check for all filenames in a particular directory using os.listdir(). Now you know the filename and can do whatever you want with it :)
See this topic for more information.
Diederik
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