Zsh function sublime open folder and directory

Question

I'm trying to write a zsh function for open files or folders from terminal.

function osub () {
if [[ -z $@ ]]; then
  /Applications/Sublime\ Text.app/Contents/SharedSupport/bin/subl $@
else
  /Applications/Sublime\ Text.app/Contents/SharedSupport/bin/subl .
fi
}

I try with $1 also. I want to open current folder in sublime if run only osub command and create new file and open it on sublime if run osub filename

If my answer helped you then please upvote it as well :) – Harald Nordgren Dec 25 '17 at 17:59 — Harald Nordgren, Dec 25 '17 at 17:59

score 1 · Accepted Answer · answered Dec 24 '17 at 00:50

1

You want to check that $@ is non-zero instead of zero which -z does. So

if [[ -n $@ ]]; then

answered Dec 24 '17 at 00:50

Harald Nordgren

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Zsh function sublime open folder and directory

1 Answers1