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It is possible to get webservice description by checking ?wsdl link of a service.

For example:

somewebsite.com/myservice.svc?wsdl

Is it possible to get a discription of a method by going to wsdl link of a method?

for example:

somewebsite.com/myservice.svc/Method?wsdl

1 Answers1

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turns out adding ?wsdl to the end of .svc method won't give XML