Variable Assignment in Bash

Asked Dec 26 '17 at 11:50

Active Dec 26 '17 at 11:53

Viewed 18 times

for i in {0..10}
do 
  args='{"args": [ "createProperty", "Property$i", "StreetNumer$i", "StreetName$i", "City$i", "State$i", "County$i", "ZipCode$i", "TaxID$i", "PropertyType$i", "CreationDate$i", "CreatingOrganization$i" ,"publicKey$i"]}'
  echo $args
done

edited Dec 26 '17 at 11:53

Cyrus

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asked Dec 26 '17 at 11:50

Sandeep Gupta

I am not able to interpolate i variable in args. it is showing $i as it is – Sandeep Gupta Dec 26 '17 at 11:51
1

Parameter expansion is not performed within single quotes. – gniourf_gniourf Dec 26 '17 at 11:54
thanks. could you please let me know the correct code for getting the expected output – Sandeep Gupta Dec 26 '17 at 12:04
I suggest to replace all `"` with `\"` and all `'` with `"` and `$args` with `"$args"`. – Cyrus Dec 26 '17 at 12:06
Thanks everyone. This trick worked. – Sandeep Gupta Dec 26 '17 at 17:33

Variable Assignment in Bash

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