How to check whether or not an integer is a perfect square?

Asked Dec 27 '17 at 20:02

Active Dec 27 '17 at 20:14

Viewed 105 times

I am pretty new to Python, and I'm trying to check whether or not an integer submitted by the user is a perfect square, and this is what I came up with:

import math
number=int(input("Insert number here: "))
root= math.sqrt(number)
if isinstance(root, int):
    print("This number is a perfect square!")
else:
    print("This number is not a perfect square!")

Now, I understand that the problem is that, if i were to input 9, the program would store root as 3.0, which would make it a floating point. But how can I fix this?

edited Dec 27 '17 at 20:14

martineau

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asked Dec 27 '17 at 20:02

Andrei Bratosin

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`if int(root) == root`. – Mazdak Dec 27 '17 at 20:04
btw, you problem is with the `isinstance` method - it returns a float type – noamgot Dec 27 '17 at 20:08
Thank you! Now it works perfectly – Andrei Bratosin Dec 28 '17 at 14:43

How to check whether or not an integer is a perfect square?

0 Answers0