How to alter behavior of JSON.parse()?

Question

I want to alter the behavior of JSON.parse is there anyway to do this in JS?

I need to do this because we are encountering some errors when trying to parse as json some data that the backend is returning as html.

Shouldn't you rather be fixing the backend so that it sends valid JSON? — JJJ, Dec 29 '17 at 12:23
If you cant fix the back end, maybe pre-process the data before parsing? — NickSlash, Dec 29 '17 at 12:33
What have you tried? It sounds like you want others to write error handling code for you — charlietfl, Dec 29 '17 at 12:36
@NickSlash i'd try that the problem is that the JSON.parse() is being called from an angularjs native piece of code which I have no control over. So that is why I wanted to change the JSON.parse() — CommonSenseCode, Dec 29 '17 at 12:37
Use an angular `httpIinterceptor`. Why is html being sent with incorrect content type header though? Or perhaps json is not sent with proper header? — charlietfl, Dec 29 '17 at 12:38

score 1 · Answer 1 · answered Dec 29 '17 at 12:27

1

Yes, you can by overriding the method:

JSON.parse = function(str) {
  console.log(str);
}
JSON.parse([1, 2]);

answered Dec 29 '17 at 12:27

vibhor1997a

Tejas Hedly · Answer 2 · 2017-12-29T13:04:02.940

-1

Why not just use try-catch to handle the response recieved from the backend as described here

function IsJsonString(str) {
    try {
        JSON.parse(str);
    } catch (e) {
        return false;
    }
    return true;
}

edited Dec 29 '17 at 13:04

answered Dec 29 '17 at 12:29

Tejas Hedly

2 Answers2