Only updating the values in loop

Question

I'm building a time count-downter. I just wanted to update the 'time' everytime instead of printing the whole thing again and again. Loops prints the same thing again and again. Like, suppose I want to print 1 to 10. The output will be 1 2 3 4 5 ... But I want 1 (and then the 1 will be removed) 2 ( it will be removed and the next one will be printed)

It is not very clear to me what you want to achieve. Please provide the current attempt, the output, and the requested output. — Willem Van Onsem, Dec 30 '17 at 19:43
Possible duplicate of [Real Time CountDown Timer In Python](https://stackoverflow.com/questions/41347676/real-time-countdown-timer-in-python) — June7, Dec 30 '17 at 19:58
You can check my code in https://trinket.io/python/c642117f02 — Aman, Dec 30 '17 at 20:32

mehrdadep · Answer 1 · 2017-12-30T21:02:50.043

\r prints a carriage return first, so remain_time is printed on top of the previous line.

import sys                #Added
import time              

while True:
  now= time.time()
  current_time= (time.asctime())
  current_hour= current_time[11:13]
  current_minute= current_time[14:16]
  current_second= current_time[17:19]
  remain_hour= 23 - int(current_hour)
  remain_minute= 60 - int(current_minute)
  remain_second= 60 - int(current_second)

  remain_time= "%sh %sm and %ss remaining" %(str(remain_hour),str(remain_minute), str(remain_second))
  sys.stdout.write('\r'+remain_time)                #Changed
  #print('\r'+remain_time,end="")      #Alternatively you can also use this
  time.sleep(1)                                     #Changed

Only updating the values in loop

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