bash script starting new shell and continuing to run commands

Question

I'm a complete noob to writing bash scripts. I'm trying to do the following:

#!/bin/bash

mkdir New_Project
cd New_Project
pipenv install ipykernel
pipenv shell
python -m ipykernel install --user --name==new-virtual-env
jupyter notebook

The problem I'm having is that after it executes pipenv shell, it starts the new shell and then doesn't execute the last two commands. When I exit the new shell it then tries to execute the remaining lines. Is there any way to get a script to run all of these commands from start to finish?

You could enter the venv with `source $(pipenv --venv)/bin/activate`. That would activate the virtual environment that you created with `pipenv install` without opening a new shell (which is what `pipenv shell` does). Then you need to use `deactivate` (not `exit`) to stop the venv. I hope that helps. — msoutopico, Mar 22 '21 at 18:24

score 13 · Accepted Answer · edited Jan 02 '18 at 07:29

13

As per the manual :

shell will spawn a shell with the virtualenv activated.

which is not what you need. Instead use run :

run will run a given command from the virtualenv, with any arguments forwarded (e.g. $ pipenv run python).

In your case, something like

pipenv run python -m ipykernel install --user --name==new-virtual-env

edited Jan 02 '18 at 07:29

Jonathan Leffler

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answered Jan 02 '18 at 07:08

sjsam

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thanks for the answer! just to clarify `pipenv run` will run any shell command i.e. `pipenv run scrapy` etc. not just python – mand Jul 20 '20 at 03:17

bash script starting new shell and continuing to run commands

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