How to declare a 16 Binary Bit Character in C/C++?

Question

Everybody knows that if you declare a 8 bit value, you can do something like

int a = B10001110;

like that vut I dont know how to declare it in 16 bit, I did something like

int b = B1000000100001111;

but this gives me error. Is there something I can do about this? I want this 16 bit format declaration.

`Everybody knows` no, most people don't know that. `B10001110` is not an 8-bit value in either C or C++ — phuclv, Jan 04 '18 at 08:44
Binary literals (starting with 0b) were standardized in c++14. See https://stackoverflow.com/questions/2611764/can-i-use-a-binary-literal-in-c-or-c — dbrank0, Jan 04 '18 at 08:46
In most implementations, use __unsigned short__ for 16 bits. — cup, Jan 04 '18 at 08:51
It's an interesting quirk of English that every statement which starts with "everybody knows" is false. — molbdnilo, Jan 04 '18 at 08:58
@molbdnilo Why is that specific for English (apart from the fact that these words are English)? — meaning-matters, Jan 04 '18 at 09:55

score 6 · Answer 1 · answered Jan 04 '18 at 08:46

C++14 allows you to use a binary literal of the form

int b = 0b1000000100001111;

The type of the literal follows the same rules as for hexadecimal literals. This is not standard C, although some C compilers allow it as an extension.

Your B notation is neither standard C nor standard C++.

meaning-matters · Answer 2 · 2018-01-04T09:53:18.080

2

Perhaps you could use this?

strtol("1000000100001111", NULL, 2);

At least it's standard C.

edited Jan 04 '18 at 09:53

answered Jan 04 '18 at 09:13

meaning-matters

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And wickedly expensive. – Bathsheba Jan 04 '18 at 09:37
@Bathsheba Indeed, but it might be something to consider depending on the application. – meaning-matters Jan 04 '18 at 09:58

How to declare a 16 Binary Bit Character in C/C++?

2 Answers2