PHP error on printing array[i] in for

Question

<html>
<body>
<?php
    $array = range(1,10);

    echo 'out func Array for Before : <br />';
    for($i = 0; $i < 10; $i++)
        echo $array[i]; // This Line!!
    echo 'End of Array Found.<br />';

    function my_multiply(&$value, $key, $factor){

        echo 'in func value(Before) - '.$value.'<br />';
        $value *= $factor;
        echo 'in func value(After) - '.$value.'<br />';
    }
    array_walk(&$array, 'my_multiply', 3);

    echo 'out func Array for Aefore : <br />';
        for($i = 0; $i < 10; $i++)
            echo $array[i]; //This Line Too.
    echo 'End of Array Found.<br />';
?>
</body>
</html>

I tried to print array[i] using echo function. but It doesn't print anything!

enter image description here

PHP 7.2 says: *"Warning: Use of undefined constant i - assumed 'i' (this will throw an Error in a future version of PHP)"*. It used to be a notice in previous versions and your interpreter is probably configured to not report the notices. — axiac, Jan 08 '18 at 07:22

Alive to die - Anant · Accepted Answer · 2018-01-08T07:00:03.630

0

You forgot $ near i.

So this:-

echo $array[i];//forgot $ near i

Need to be:-

echo $array[$i];// now $i is correct variable and will work fine

Every-where

edited Jan 08 '18 at 07:00

answered Jan 08 '18 at 06:55

Alive to die - Anant

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Thank you! i First learn php... – WishSKY Jan 08 '18 at 06:57
Thank you. I accepted the answer. – WishSKY Jan 08 '18 at 13:25
@WishSKY glad to help you :):) – Alive to die - Anant Jan 08 '18 at 14:27

PHP error on printing array[i] in for

1 Answers1