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I have a structure List[Array[Double]] and I want to convert to a DenseMatrix. I have this solution but I think there might be a better way:

val data = List[Array[Double]]
val rows = data.length;
val cols = data(0).length;
val matrix = DenseMatrix.zeros[Double](rows, cols)
for (i <- 0 until data.length) {
  for (j <- 0 until data(i).length) {
    matrix(i,j)= data(i)(j)

  }
}

I've been through the Breeze docs but didn't find anything. Is there a better way?

MLeiria
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1 Answers1

7

You can try this:

val matrix = DenseMatrix(data:_*)

EDIT1

For an explanation of how it works, you can consider data: _* as expansion into variable arguments. For example if 

val data = List[Array[Double]](Array(1.0, 1.0), Array(2.0, 2.0))

Then DenseMatrix(data:_*) is same as saying DenseMatrix(Array(1.0, 1.0), Array(2.0, 2.0))

For more details:

tuxdna
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