I have two dataframes A and B:
For example:
import pandas as pd
import numpy as np
In [37]:
A = pd.DataFrame({'Start': [10, 11, 20, 62, 198], 'End': [11, 11, 35, 70, 200]})
A[["Start","End"]]
Out[37]:
Start End
0 10 11
1 11 11
2 20 35
3 62 70
4 198 200
In [38]:
B = pd.DataFrame({'Start': [8, 5, 8, 60], 'End': [10, 90, 13, 75], 'Info': ['some_info0','some_info1','some_info2','some_info3']})
B[["Start","End","Info"]]
Out[38]:
Start End Info
0 8 10 some_info0
1 5 90 some_info1
2 8 13 some_info2
3 60 75 some_info3
I would like to add column info to dataframe A based on if the interval (Start-End) of A overlaps with the interval of B. In case, the A interval overlaps with more than one B interval, the info corresponding to the shorter interval should be added.
I have been looking arround how to manage this issue and I have found kind of similar questions but most of their answers are using iterrows()
which in my case, as I am dealing with huge dataframes is not viable.
I would like something like:
A.merge(B,on="overlapping_interval", how="left")
And then drop duplicates keeping the info coming from the shorter interval.
The output should look like this:
In [39]:
C = pd.DataFrame({'Start': [10, 11, 20, 62, 198], 'End': [11, 11, 35, 70, 200], 'Info': ['some_info0','some_info2','some_info1','some_info3',np.nan]})
C[["Start","End","Info"]]
Out[39]:
Start End Info
0 10 11 some_info0
1 11 11 some_info2
2 20 35 some_info1
3 62 70 some_info3
4 198 200 NaN
I have found this question really interesting as it suggests the posibility of solving this issue using pandas Interval object. But after lots attempts I have not managed to solve it.
Any ideas?