I followed this tutorial http://www.javawebtutor.com/articles/web-services/rest/creating-web-service-with-maven-jersey.php
and it accesses the API using a link like this
localhost:8080/RESTfullApp/rest/hello/inputhere
I have a requirement to replace an existing RESTFul API with a link like this:
localhost:8080/Sample.pl?Task=GetStuff&StuffNumber=1
Things done:
@Path("/Sample.pl?")
public class HelloWorldService {
@GET
@Path("Task=GetStuff&StuffNumber={name}")
public Response getMsg(@PathParam("name") String name) {
String output = "Stuff num : " + name;
return Response.status(200).entity(output).build();
}
}
web.xml: what to change here?
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>RESTfulExample</display-name>
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.jwt.rest</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/*I dont know what to do here*/</url-pattern>
</servlet-mapping>
</web-app>
