How to define a string like: sss" + str1 + "ddd

Question

string str1="xxx";
string str2=@"sss" + str1 + "ddd";
Console.WriteLine(str2);

The above code gives:

sssxxxddd

But what I want is:

sss" + str1 + "ddd

How to do that?

https://stackoverflow.com/questions/14480724/escape-double-quotes-in-string — BJ Myers, Jan 11 '18 at 01:50
To obtain a " within the string itself, you need to write "" — asthman, Jan 11 '18 at 02:02

Jonathan Wood · Accepted Answer · 2018-01-11T04:31:34.427

4

You can escape the quotes by preceding them with a backslash (\).

string str1 = "xxx";
string str2 = "sss\" + str1 + \"ddd";
Console.WriteLine(str2);

For strings prefixed with the @ character, quotes are escaped by placing two together (i.e., string str2 = "sss"" + str1 + ""ddd").

edited Jan 11 '18 at 04:31

answered Jan 11 '18 at 01:53

Jonathan Wood

65,341
71
269
466

Thanks! the placing two quotes to escape when using @ is exactly what I want to know! – Jan 11 '18 at 04:30

Gordon · Answer 2 · 2018-01-11T02:06:27.407

3

Here you go:

 Console.WriteLine("sss\" + str1 + \"ddd");

edited Jan 11 '18 at 02:06

answered Jan 11 '18 at 01:53

Gordon

516
1
3
13

This does not answer the question. – Enigmativity Jan 11 '18 at 02:01
@Enigmativity I changed the answer, but I think he/she can figure it out with my original answer. I tend not to give direct "copy and paste" answer to questions. – Gordon Jan 11 '18 at 02:07
Yes this works, but I'm more interested in knowing how to do it WITHOUT removing @. My question was not clear enough. Thank you anyway. – Jan 11 '18 at 04:32

Xss · Answer 3 · 2018-01-11T02:05:43.310

3

        string str1 = "xxx";
        string str2 = @"sss"" + str1 + ""ddd";
        Console.WriteLine(str2);

        string str3 = "xxx";
        string str4 = "sss\" + str1 + \"ddd";
        Console.WriteLine(str4);
        Console.ReadKey();

edited Jan 11 '18 at 02:05

answered Jan 11 '18 at 01:56

Xss

211
1
12

The second way does not output `sss" + str1 + "ddd`. – Enigmativity Jan 11 '18 at 02:01

Harsh Mehta · Answer 4 · 2018-01-11T02:03:12.727

-2

string str1="xxx";
string str2=@"sss""" + str1 + @"""ddd";
Console.WriteLine(str2);

or

string str1="xxx";
string str2="sss\"" + str1 + "\"ddd";
Console.WriteLine(str2);

This will give you an answer like: sss"xxx"ddd. If you want an answer like sss" + str1 + "ddd then you replace the second line with this: string str2=@"sss"" + str1 + ""ddd";

edited Jan 11 '18 at 02:03

answered Jan 11 '18 at 01:57

Harsh Mehta

20
4

This does not output `sss" + str1 + "ddd`. – Enigmativity Jan 11 '18 at 02:01
I thought in place of str1 you want a value of string str1 which you declared here – Harsh Mehta Jan 11 '18 at 02:04
That's not what the OP asked for. I must say he's asked a weird question, but he's been quite specific. – Enigmativity Jan 11 '18 at 02:27

OreaSedap · Answer 5 · 2018-01-11T02:13:50.203

-3

You may try this

string str1="xxx";
string str2=@"sss\"" + str1 + "\"ddd";
Console.WriteLine(str2);

EDITED

string str1 = "\"xxx\""; string str2 = "sss" + str1 + "ddd"; Console.WriteLine(str2); Console.ReadLine();

edited Jan 11 '18 at 02:13

answered Jan 11 '18 at 01:58

OreaSedap

21
7

This does not output `sss" + str1 + "ddd`. – Enigmativity Jan 11 '18 at 02:01
@Enigmativity my bad, I missplace the quote. I had update my answer – OreaSedap Jan 11 '18 at 02:14
Your edit outputs `sss"xxx"ddd` - that's not what the OP wants. – Enigmativity Jan 11 '18 at 02:25
@Enigmativity, how you know that's is not what he want? He not even respond to each of the answer yet. By looking at his question, that is what the answer suppose to be. IMO – OreaSedap Jan 11 '18 at 02:35
@Enigmativity My bad. I see, he want the "+" and double quotes included in the output. The question kinda confusing to me. – OreaSedap Jan 11 '18 at 02:40

How to define a string like: sss" + str1 + "ddd

5 Answers5