Regular Expression for first address line with special requirements

Asked Jan 11 '18 at 13:36

Active Jan 11 '18 at 14:09

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I am very new to regular expressions and I am attempting to write one that allows me to validate addresses (specifically, a line 1 of an address. not full) with the following special requirements:

Allowed values: alphanumeric, -, ', ., #, /, (comma), [space]

I've created the following, but it doesn't work for something simple as "110 W Cityline Dr"

Regular Expression: ^[a-zA-Z 0-9.\,#-\'/]*$

EDIT: Per Suggestion, I am using the following: ^[a-zA-Z 0-9-.\,#\'/]*$. This seems to be working.

edited Jan 11 '18 at 14:09

asked Jan 11 '18 at 13:36

Anticrombie23

[`^[a-zA-Z 0-9.\,#-\'/]*$` matches `110 W Cityline Dr`](https://regex101.com/r/xAi1RD/1) though you should know that `-` here creates a range between `#` (index 35) and `'` (index 39). – Wiktor Stribiżew Jan 11 '18 at 13:38
Apologies, my JUNIT's were incorrectly organized! -- so what would be the proper regular expression to remove the range? – Anticrombie23 Jan 11 '18 at 13:43
Move the `-` to the end or start of the character class, or escape it. – Wiktor Stribiżew Jan 11 '18 at 13:44

Regular Expression for first address line with special requirements

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