sed command to print lines between two patterns

Question

I am trying to print lines between two patterns through sed command. But I want to include the line containing Pattern1 in the result and exclude the Pattern2. For ex:

/PAT1/
line 1
line 2
line 3
/PAT2/

The desired output is :

/PAT1/
line 1
line 2
line 3

I have tried this :

sed -n '/PAT1/,/PAT2/{/PAT2/{d};p}' Input_File

But it is excluding both the patterns.

Possible duplicate of [How to select lines between two patterns?](https://stackoverflow.com/questions/38972736/how-to-select-lines-between-two-patterns) — Sundeep, Jan 12 '18 at 04:51
May also be written `sed '/pattern1/,/pattern2/!d;/pattern2/d' file` — potong, Jan 12 '18 at 11:01
Is there an issue where the second pattern would match the first? e.g. from `Keyword:` to `:` , where I'd like the lines from and including `Keyword: ...` up to but excluding the next keyword line. — simon.watts, Mar 05 '19 at 12:33

score 1 · Accepted Answer · answered Jan 11 '18 at 22:29

1

You can do it with awk: awk '/patt1/{flag=1}/patt2/{flag=0}flag' input_file

If input_file is:

awk '/222/{flag=1}/444/{flag=0}flag' input_file

gives:

222
333

answered Jan 11 '18 at 22:29

John3136

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sed command to print lines between two patterns

1 Answers1