JavaScript function expression and function declaration, am I right in my understanding?

Question

Am I right in my understanding of this code. We call the function with an anonymous function. It firstly console logs the function ( as in the function structure, it does not run the function. It then runs the function when it comes across a();

Is this correct?

var runIt = function(a) {
    console.log(a);
    a();
};

runIt(function({
    var b = " Now";
    console.log("Running" + b); 
});

Yes that is correct. A function call consists of a reference to a function followed by a parenthesized argument list. — Pointy, Jan 16 '18 at 14:58
@Pointy - one of us is not reading that correctly because I don't see the 2nd part of that working at all. — Reinstate Monica Cellio, Jan 16 '18 at 14:59
`runIt(function({` should be `runIt(function(){` otherwise it will fail — StudioTime, Jan 16 '18 at 15:03
@Archer oh right, yes the syntax is incorrect in the call to `runIt()`. But my take on what was being asked is that in the OP's actual test code that wasn't a problem. — Pointy, Jan 16 '18 at 15:04

score 1 · Answer 1 · answered Jan 16 '18 at 15:01

We call the function with an anonymous function. It firstly console logs the function (as in: the function structure), it does not run the function. It then runs the function when it comes across a().

Is this correct?

Yes.

JavaScript function expression and function declaration, am I right in my understanding?

No. This code has nothing to do with function expressions vs function declarations.

JavaScript function expression and function declaration, am I right in my understanding?

1 Answers1