What kind of number is aa568 and how do I convert to it from decimal in Java?

Question

I assume aa568 uses a different base than 10.

What type of number is this most likely?

And how do you convert a decimal number into this base using Java?

Answer 1

Assuming it is hexadecimal (0-9 + A-F instead of 0-9), you can convert it from hex to decimal as follows:

int i = Integer.parseInt(hexStr,16);

Where 16 is the base of the number system. Decimal is base 10, hexadecimal is base 16. And back from decimal to hexadecimal:

String hexStr = Integer.toHexString(i);

Answer 2

Could it be hexadecimal? If it is then just precede that by 0x ie. 0xaa568.

Answer 3

What kind of number may depend on the context, of none of the above fits, then it may be an integer sequence, I looked it up in the online encyclopedia of known integer sequences. Example a000045 is a Fibonacci sequence, (Formerly M0692 N0256), if it has to do with math it may also be a library reference to a paper written by AA. Only the Context can tell. Mathnet.ru had one reference "The behavior of the Lebesgue constants of two-dimensional Fourier sums over polygons" which fits the questioned number aa568.

Answer 4

Converting a number into a hexadecimal string can be done by the Integer.toHexString() method:

int number = 697704;

System.out.println(Integer.toHexString(number));

will print "aa568".

Answer 5

I'd assume that it's hexadecimal and more typically written 0xAA568 which is decimal 697704.

If you're asking how you would print a decimal number in a hexadecimal representation using Java ... see this stackoverflow article.